Latest 0.1.4
Homepage https://github.com/fattomhk/JustJSON
License MIT
Platforms ios 8.0, requires ARC
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Example

To run the example project, clone the repo, and run pod install from the Example directory first.

Full Example

You may find an example project here. It uses JustJSON to parse json data to data model.

Requirements

Installation

CocoaPods

CocoaPods is a dependency manager for Cocoa projects. You can install it with the following command:

$ gem install cocoapods

To integrate JustJson into your Xcode project using CocoaPods, specify it in your Podfile:

use_frameworks!

pod 'JustJson'

Then, run the following command:

$ pod install

Example

Convert to Dictionary from JSON string

let dict = jsonStr.toDictionary()

Convert Dictionary [String: Any] to JSON string

let jsonString = dict.toJSONStr()

Get Data from Dictionary

let foo = dict[keyPath: "first.second.abc 123"] //return an optional Any
let foo = dict[string: "first.second.abc 123"] //return an optional String
let foo = dict[dict: "first.second.abc 123"] //return an optional Dictionart
let foo = dict[array: "first.second.abc 123"] //return an optional Array

Looping

for foo in dict[arrayValue: "first.second.foos"] {
  print(foo)
}

Object Mapping

Here comes a Dictionary:

userGroup = ["users": [
                [
                    "id" : "1",
                    "name" : "Apple",
                    "age" : 18
                ],
                [
                    "id" : "2",
                    "name" : "Boy",
                    "age" : 19
                ],
                [
                    "id" : "3",
                    "name" : "Cat",
                    "age" : 30
                ],
            ]
        ]

A User model:

struct User: JJMappable {
    var id: String?
    var name: String?
    var age: Int

    init(map: JJMapper) {
        id = map[string: "id"]
        name = map[string: "name"]
        age = map[intValue: "age"]
    }
}

A UserGroup model:

struct UserGroup: JJMappable {
    var users: [User]?

    init(map: JJMapper) {
        users = User.from(map[arrayValue: "users"])
    }
}

If you want to map a user

let data = userGroup[arrayValue: "users"][1] as! [String: Any]
let user: User? = User.from(data)

If you want to get users

let users: [Users]? = User.from(userGroup[arrayValue: "users"])

Nested mapping

let _userGroup = UserGroup.from(userGroup)

More Exampes:

Test case

Author

Horst Leung

Thanks

Ole Begemann [https://oleb.net/blog/2017/01/dictionary-key-paths/]

License

JustJson is available under the MIT license. See the LICENSE file for more info.

Latest podspec

{
    "name": "JustJson",
    "version": "0.1.4",
    "license": {
        "type": "MIT",
        "file": "LICENSE"
    },
    "summary": "JustJson is a simple project for handling JSON with keypaths. Copying the logic from https://oleb.net/blog/2017/01/dictionary-key-paths/",
    "description": "SwiftyJSON is great but I want a lazy way to access the data.nJustJson is a simple project for handling JSON with keypaths.nOle Begemann gave a good example on how to make it.",
    "requires_arc": true,
    "homepage": "https://github.com/fattomhk/JustJSON",
    "authors": {
        "PROJECT_OWNER": "[email protected]"
    },
    "source": {
        "git": "https://github.com/fattomhk/JustJSON.git",
        "tag": "0.1.4"
    },
    "platforms": {
        "ios": "8.0"
    },
    "source_files": "Source/*.swift",
    "pushed_with_swift_version": "3.0"
}

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